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x^2+45x+12=-188
We move all terms to the left:
x^2+45x+12-(-188)=0
We add all the numbers together, and all the variables
x^2+45x+200=0
a = 1; b = 45; c = +200;
Δ = b2-4ac
Δ = 452-4·1·200
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-35}{2*1}=\frac{-80}{2} =-40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+35}{2*1}=\frac{-10}{2} =-5 $
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